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Tonnage of a Stip.

It will also be worth while to add the following exact rule of Mr Parkins, who was many years foreman of the shipwrights in Chatham dockyard.

1. For Men of War.

Take the length of the gun-deck from the rabbet of the stem to the rabbet of the stern post. of this is to be assumed as the length for tonnage, = L. Take the extreme breadth from outside to outside of the plauk; add this to the length, and take of the sum; call this the depth for tonnage, = D.

Set up this height from the limber strake, and at that height take a breadth also from outside to outside of plank in the timber when the extreme breadth is found, and another breadth in the middle between that and the limber strake; add together the extreme breadth and these two breadths, and take of the sum for the breadth for tonnage, D.

Multiply L, D, and B together, and divide by 49. The quotient is the burthen in tons.

The following proof may be given of the accuracy of this rule. Column 1. is the tonnage or burthen by the king's measurement; col. 2. is the tonnage by this rule; and, col. 3. is the weight actually received on board these ships at Blackstakes:

also the additional weight necessary to bring her down to the load water line.

In order to construct this scale for a given ship, it is necessary to calculate the quantity of water displaced by the keel, and by that part of the bottom below each water line in the draught. Since the areas of the several water lines are already computed for the eighty-gun ship laid down in Plates CCCCXC. and CCCCXCI. the contents of these parts may hence be easily found for that ship, and are as follow.

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3d w. line

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23574-63 778 1795

London

90

1845 1575

1677

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1614

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1369 1141

965

Dist. 31 and 7

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870

886

2d. w. line S

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Daphne

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51476.21700 1231

79288.32619 766

8

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Scale of Solidity.

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Add the length of the lower deck to the extreme breadth from outside to outside of plank; and take of the sum for the depth for tonnage, = D.

Set up that depth from the limber strake, and at this height take a breadth from outside to outside. Take another at of this height, and another at of the height. Add the extreme breadth and these three breadths, and take the 4th of the sum for the breadth for tonnage, B.

Multiply L, D, and B, and divide by 36. The quotient is the burthen in tons.

This rule rests on the authority of many such trials, as the following:

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Construct any convenient scale of equal parts to represent tons, as scale N° 1. and another to represent feet, as N° 2.

Plate

60

Draw the line AB (fig. 36.) limited at A, but pro- ccccxen. duced indefinitely towards B. Make AC equal to the depth of the keel, 2 feet 3 inches from scale N° 2. and Constructhrough C draw a line parallel to AB, which will re- t'on of the scale of sopresent the upper edge of the keel; upon which set off lidity for Cc equal to 21 tons 1855 lbs. taken from scale N° 1. the ship of Again, make AD equal to the distance between the eighty lower edge of the keel and the fifth water line, namely, guns. 6 feet 4 inches, and a line drawn through D parallel to AB will be the representation of the lower water line; and make Db equal to 305 tons 848 lbs. the corresponding tonnage. In like manner draw the other water lines, and lay off the corresponding tonnages accordingly then through the points A, c, b, c, f, g, h, draw the curve Ac befgh. Through h draw h B perpendicular to AB, and it will be the greatest limit of the quantity of water expressed in tons displaced by the bottom of the ship, or that when she is brought down to the load water line. And since the ship displaces 1788 tons at her light water-mark, take therefore that quantity from the scale N° 1. which being laid upon AB from A to K, and KL drawn perpendicular to AB, will be the representation of the light

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water

Scale of water line for tonnage.
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Hence the scale will be com

Let it now be required to find the number of cubic Use of the feet displaced when the draught of water is 17 feet, and Dove seale. the number of additional tons necessary to bring her down to the load water mark.

-Take the given draught of water 17 feet from the -scale N° 2, which laid from it will reach to I; through which draw the line IMN parallel to AB, and intersecting the curve in AC; then the distance IM applied to the scale N° 1, will measure about 2248 tons, the displacement answerable to that draught of water; and MN applied to the same scale will measure about 1405 tons, the additional weight necessary to bring her down to the load water mark. Also the nearest distance between M and the line KL will measure about 460 tons, the weight already on board.

It will conduce very much to facilitate this operation to divide KB into a scale of tons taken from the scale N° 1, beginning at B, and also h L, beginning at h. Then when the draught of water is taken from the scale N° 2, and laid from it to I, as in the former example, and IMN drawn parallel to AB, and intersecting the curve in M. Now through M draw a line perpendicular to AB, and it will meet KB in a point representing the number of tons aboard, and also / L in a point denoting the additional weight necessary to load her.

Again, if the weight on board be given, the corresponding draught of water is obtained as follows,

Find the given number of tons in the scale KB, through which draw a line perpendicular to AB; then through the point of intersection of this line with the curve draw another line parallel to AB. Now the distance between A and the point where the parallel intersected AH being applied to the scale N° 2, will give the draught of water required.

Any other case to which this scale may be applied

will be obvious.

Book II. Containing the Properties of Ships, &c.

CHAP. I. Of the Equilibrium of Ships.

um of

Ships.

the pressure exerted upon EF is expressed by EFXIK, Equilibri
IK being the depth of EF or CD; the density of the
fluid being supposed equal to 1. In like manner the
pressure upon CD is equal to CDXIK. Now since the
pressure is in a direction perpendicular to the surface,
draw therefore the line EL perpendicular to EF, and
DM perpendicular to DC, and make each equal to the
depth IK, below the surface. Now the effort or pressure
of the fluid upon EF will be expressed by EFX EL,
and that upon CD by CDx DM. Complete the paral-
lelograms ON, QS, and the pressure in the direction
EL is resolved into EN, EO, the first in a horizontal,
and the second in a vertical direction. In like manner,
the pressure in the direction DM is resolved into the
pressures DS, DQ. Hence the joint effect of the pres-
sures in the horizontal and vertical directions, namely,
EFXEN, and EFX EO, will be equal to EFXEL:
For the same reason, CDx DP+CD×DQ=CDX
DM. But the parts of the pressures in a horizontal di-
rection EFX EN and CDXDP, are equal. For, be-
cause of the similar triangles ENL, ERF, and DPM,
EL EF DM DC
: Hence DM
DSC, we have EN-FR DP-CS
XCS-DPx DC, and ELX FR=EN×EF. Now
since EL DM, and FR=CS, therefore ELX FR=
DMX CS=DP × DC=EN × EF. Hence since EFX
EN DP XCD, the effects of the pressures in a bori-
zontal direction are therefore equal and contrary, and
consequently destroy each other.

and

The pressure in a vertical direction is represented by EOXEF, DQx DC, &c. which, because of the similar triangles EOL, ERF, and DLM, DSC, become EL× ER, DM × DS, &c. or IK × ER, IK × DS, &c. By applying the same reasoning to every other portion of the surface of the immersed part of the body, it is hence evident that the sum of the vertical pressures is equal to the sum of the corresponding displaced columns

of the fluid.

62

of a ship

Hence a floating body is pressed upwards by a force The weight equal to the weight of the quantity of water displaced; equal to and since there is an equilibrium between this force and that of the the weight of the body, therefore the weight of a float- quantity of ing body is equal to the weight of the displaced fluid water dis(K). Hence also the centre of gravity of the body placed. and the centre of gravity of the displaced fluid are in And the the same vertical, otherwise the body would not be at centre of

rest.

SINCE the pressure of fluids is equal in every direc-
tion, the bottom of a ship is therefore acted upon by
the fluid in which it is immersed; which pressure, for
any given portion of surface, is equal to the product of
that portion by the depth and density of the fluid or
it is equal to the weight of a column of the fluid whose CHAP. II. Upon the Efforts of the Water to bend a
base is the given surface and the altitude equal to the
distance between the surface of the fluid and the centre
of gravity of the surface pressed. Hence a floating
body is in equilibrio between two forces, namely, its
gravity and the vertical pressure of the fluid; the hori-
zontal pressure being destroyed.

Plate
Let ABC (fig, 49.) be any body immersed in a fluid
ccccxciv. whose line of floatation is GH: hence the pressure of
the fluid is exerted on every portion of the surface of the
immersed part AFCH. Let EF, CD be any two small
portions contained between the lines ED, FC, parallel
to each other, and to the line of floatation GH: then

Vessel.

63

gravity of both are in the same vertical.

WHEN it is said that the pressure of the water upon Theorie the immersed part of a vessel counterbalances its weight, Complette, &c. par

it is supposed that the different parts of the vessel are so Fuler.
closely connected together, that the forces which act translated
upon its surface are not capable of producing any change. by Watson.
For we may easily conceive, if the connection of the
parts were not sufficiently strong, the vessel would run
the risk either of being broken in pieces, or of suffering
some alteration in its figure.

The vessel is in a situation similar to that of a rod
ᎪᏴ

(K) Uoni principle the weight and tonnage of the 80 gun ship laid down were calculated.

Vessel.

Tfits of AB (fig. 50.), which being acted upon by the forces 2- Water A a, Cc, Dd, Bb, may be maintained in equilibrio, to bend a provided it has a sufficient degree of stiffness: but as soon as it begins to give way, it is evident it must bend in a convex manner, since its middle would obey the forces Cc and Dd, while its extremities would be actually drawn downwards by the forces A a and B b.

Plate

The vessel is generally found in such a situation; and since similar efforts continually act whilst the vessel is immersed in the water, it happens but too often that the keel experiences the bad effect of a strain. It is therefore very important to inquire into the true cause of this accident.

For this purpose, let us conceive the vessel to be divided into two parts by a transverse section through the vertical axis of the vessel, in which both the centre of gravity G (fig. 51.) of the whole vessel and that of ccccxcv. the immersed part are situated: so that one of them 5. will represent the head part, and the other that of the stern, each of which will be considered separately. Let g be the centre of gravity of the entire weight of the first, and that of the immersed part corresponding. In like manner, let y be the centre of gravity of the whole after part, and w that of its immediate portion. Now it is plain, that the head will be acted upon by the two forces g m and o n, of which the first will press it down, and the latter push it up. In the same manner, the stern will be pressed down by the force y, and pushed by the force wy. But these four forces will maintain themselves in equilibrium, as well as the total forces reunited in the points G and O, which are equivalent to them; but whilst neither the forces before 64 The cause nor those behind fall in the same direction, the vessel of a ship's will evidently sustain efforts tending to bend the keel bogging, upwards, if the two points are nearer the middle than the two other forces gm and yμ. A contrary effect would happen if the points and were more distant from the middle than the points g and y.

65 and sag

ging.

Practical

But the first of these two causes usually takes place almost in all vessels, since they have a greater breadth towards the middle, and become more and more narrow towards the extremities; whilst the weight of the vessel is in proportion much more considerable towards the extremities than at the middle. From whence we see, that the greater this difference becomes, the more also will the vessel be subject to the forces which tend to bend its keel upwards. It is therefore from thence that we must judge how much strength it is necessary to give to this part of the vessel, in order to avoid such a consequence.

If other circumstances would permit either to load the vessel more in the middle, or to give to the part immer sed a greater capacity towards the head and stern, such an effect would no longer be apprehended. But the destination of most vessels is entirely opposite to such an arrangement: by which means we are obliged to strengthen the keel as much as may be necessary, in

order to avoid such a disaster.

We shall conclude this chapter with the following practical observations on the hogging and sagging of ships by Mr Hutchinson of Liverpool:

"When ships with long floors happen to be laid aSeaman. dry upon mud or sand, which makes a solid resistance ship, p. 13. against the long straight floors aniidships, in comparison with the two sharp ends, the entrance and run meet with

Vessel.

little support, but are pressed down lower than the flat Efforts of of the floor, and in proportion hogs the ship amid- the Water ships; which is too well known from experience to oc- to bend a casion many total losses, or do so much damage by hogging them, as to require a vast deal of trouble and expence to save and repair them, so as to get the hog taken out and brought to their proper sheer again: and to do this the more effectually, the owners have often been induced to go to the expence of lengthening them; and by the common method, in proportion as they adds to the burden of these ships, by lengthening their too long straight floors in their main bodies amidships, so much do they add to their general weakness to hearhardships either on the ground or afloat; for the scantling of their old timber and plank is not proportionable to bear the additional burden that is added to them.

"But defects of this kind are best proved from real and incontestable facts in common practice. At the very time I was writing upon this subject, I was called upon for my advice by the commander of one of those strong, long, straight floored ships, who was in much trouble and distraction of mind for the damage his ship had taken by the pilot laying her on a hard, gentle slop ing sand, at the outside of our docks at Liverpool, where it is common for ships that will take the ground to lie for a tide, when it proves too late to get into our wetdocks. After recommending a proper ship carpenter, I went to the ship, which lay with only a small keel, yet was greatly hogged, and the butts of her upper works strained greatly on the lee side; and the seams of her bottom, at the lower futtock heads, vastly opened on the weather side all which strained parts were agreed upon not to be caulked, but filled with tallow, putty, or clay, &c. with raw bullocks hides, or canvas, nailed with battons on her bottom, which prevented her sinking with the flow of the tide, without hindering the pressure of water from righting and closing the seams again as she floated, so as to enable them to keep her free with pumping. This vessel, like many other instances of ships of this construction that I have known, was saved and repaired at a very great expence in our dry repairing docks. And that their bottoms not only hog upwards, but sag (or curve) down.wards, to dangerous and fatal degrees, according to the strain or pressure that prevails upon them, will be proved from the following facts:

:

"It has been long known from experience, that when ships load deep with very heavy cargoes or materials · that are stowed too low, it makes them so very laboursome at sea, when the waves run high, as to roll away their masts; and after that misfortune causes them to labour and roll the more, so as to endanger their working and straining themselves to pieces: to prevent which, it has been long a common practice to leave a great part of their fore and after holds empty, and to stow them as high as possible in the main body at midships, which causes the bottoms of these long straightfloored ships to sag downwards, in proportion as the weight of the cargo stowed there exceeds the pressure of the water upwards, so much as to make them dangerously and fatally leaky.

"I have known many instances of those strong ships. of 500 or 600 tons burdens built with long straight floors, on the east coast of England, for the coal and timber trade, come loaded with timber from the Baltic

Vessel.

said to be possessed of stability; or it will continue in Stability t its inclined state; or, lastly, the inclination will increase Ships. until the vessel is overturned. With regard to the first case, it is evident that a sufficient degree of stability is necessary in order to sustain the efforts of the wind; but neither of the other two cases must be permitted to have place in vessels.

Efforts of to Liverpool, where they commonly load deep with the Water rock salt, which is too heavy to fill their holds, so that to bend a for the above reasons they stowed it high amidships, and left large empty spaces in their fore and after holds, which caused their long straight floors to sag downwards, so much as to make their hold stanchions amidships, at the main hatchway, settle from the beams three or four inches, and their mainmasts settle so much as to oblige them to set up the main rigging when rolling hard at sea, to prevent the masts being rolled away; and they were rendered so leaky as to be obliged to return to Liverpool to get their leaks stopped at great expence. And in order to save the time and expence in discharging them, endeavours were made to find out and stop their leaks by laying them ashore dry on a level sand; but without effect: for though their bottoms were thus sagged down by their cargoes when afloat, yet when they came a-dry upon the sand, some of their bottoms hogged upwards so much as to raise their mainmasts and pumps so high as to tear their coats from their decks; so that they have been obliged to discharge their cargoes, and give them a repair in the repairing dock, and in some to double their bottoms, to enable them to carry their cargoes with safety, stowed in this manner. From this cause I have known one of these strong ships to founder.

"Among the many instances of ships that have been distressed by carrying cargoes of lead, one saited from hence bound to Marseilles, which was soon obliged to put back again in great distress, having had four feet water in the hold, by the commander's account, owing to the ship's bottom sagging down to such a degree as made the hold stanchions settle six inches from the lower deck beams amidships; yet it is common with these long straight floored ships, when these heavy cargoes are discharged that make their bottoms sag down, then to hog upwards: so that when they are put into a dry repairing dock, with empty holds, upon straight blocks, they commonly either split the blocks close fore and aft, or damage their keels there, by the whole weight of the ship lying upon them, when none lies upon the blocks under the flat of their floors amidships, that being hogged upwards; which was the case of this ship's bottom; though sagged downwards six inches by her cargo, it was now found hogged so much that her keel did not touch the blocks amidships, which occasioned so much damage to the after part of the keel, as to oblige them to repair it; which is commonly the case with these ships, and therefore deserving particular

notice."

In order to prevent these defects in ships, "they should all be built with the floors or bottoms lengthwise, to form an arch with the projecting part downwards, which will naturally not only contribute greatly to prevent their taking damage by their bottoms hogging and straining upwards, either aground or afloat, as has been mentioned, but will, among other advantages, be a help to their sailing, steering, staying, and waring."

CHAP. III. Of the Stability of Ships.

WHEN a vessel receives an impulse or pressure in a horizontal direction, so as to be inclined in a small degree, the vessel will then either regain its former position as the pressure is taken off and is in this case

Let CED (fig. 52.) be the section of a ship passing Fig. 52. through its centre of gravity, and perpendicular to the sheer and floor plans; which let be in equilibrium in a fluid; AB being the water line, G the centre of gravity of the whole body, and g that of the immersed part AEB. Let the body receive now a very small inclination, so that a Eb becomes the immersed part, and its centre of gravity. From y draw y M perpendicular to a b, and meeting g G, produced, if necessary, in M. If, then, the point M thus found is higher than G the centre of gravity of the whole body, the body will, in this case, return to its former position, the pressure being taken off. If the point M coincides with G, the vessel will remain in its inclined state; but if M be below G, the inclination of the vessel will continually increase until it is entirely over

set.

The point of intersection M is called the metacenter, and is the limit of the altitude of the centre of gravity of the whole vessel. Whence it is evident, from what has already been said, that the stability of the vessel increases with the altitude of the metacenter above the centre of gravity: But when the metacenter coincides with the centre of gravity, the vessel has no tendency whatever to move out of the situation into which it may be put. Thus, if the vessel be inclined either to the right or left side, it will remain in that position until a new force is impressed upon it: in this case, therefore, the vessel would not be able to carry sail, and is hence unfit for the purposes of navigation. If the metacenter is below the common centre of gravity, the vessel will instantly overset.

As the determination of the metacenter is of the utmost importance in the construction of ships, it is therefore thought necessary to illustrate this subject more particularly.

Let AEB (fig. 52.) be a section of a ship perpendicular to the keel, and also to the plane of elevation, and passing through the centre of gravity of the ship, and also through the centre of gravity of the immersed part, which let be g.

Now let the ship be supposed to receive a very small inclination, so that the line of floatation is a, b, and y the centre of gravity of the immersed part a Eb. From y draw M perpendicular to a b, and intersecting GM in M, the metacenter, as before. Hence the pressure of the water will be in the direction M.

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In order to determine the point M, the metacenter, the position of with respect to the lines AB and g G, must be previously ascertained. For this purpose, let the ship be supposed to be divided into a great number of sections by planes perpendicular to the keel, and parallel to each other, and to that formerly drawn, these planes being supposed equidistant. Let AEB (fig. 53-) Fig. 53 be one of these sections, g the centre of gravity of the immersed part before inclination, and y the centre of gravity of the immersed part when the ship is in its inclined state; the distance gy between the two centres

Ships.

Stability of of gravity in each section is to be found. Let AB be the line of floatation of the ship when in an upright state, and a b the water line when inclined. Then, because the weight of the ship remains the same, the quantity of water displaced will also be the same in both cases, and therefore AEB-a E b, each sustaining the same part of the whole weight of the ship. From each of these take the part AE b, which is common to both, and the remainders AO a, BO b will be equal; and which, because the inclination is supposed very small, may be considered as rectilineal triangles, and the point O the middle of AB.

Now, let H, I, K, be the centres of gravity of the spaces AO a, AE b, and BO b, respectively. From these points draw the lines H h, I i, and K k, perpendicular to AB, and let IL be drawn perpendicular to EO. Now to ascertain the distance y q of the centre of gravity of the part a E 6 from the line AB, the momentum of a Eb with respect to this line must be put equal to the difference of the momentums of the parts AE 6, AO a, which are upon different sides of * Bezout's AB *. Mechanique, art.

203.

Hence a Ebx7q, or AEBXyq=AE b XIi-AO axHh. But since g is the common centre of gravity of the two parts AEb, BOb, we have therefore AEBxg0=AE bxIi+BO b×K k. Hence by expunging the term AE bxIi from each of these equations, and comparing them, we obtain AEBX79 AEBxg O-BO bxK k-AO axHh.

Now, since the triangles AO a, BO b, are supposed infinitely small, their momentums or products, by the infinitely little lines Hh, Kk, will also be infinitely small with respect to AEBxg O; which therefore being rejected, the former equation becomes ABXYq AEBx g 0, and hence yq=g 0. Whence the centres of gravity, g, being at equal distances below AB, the infinitely little line yg is therefore perpendicular to EO. For the same reason g y, fig. 52. may be considered as an arch of a circle whose centre is M.

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Hence V X gy=s,=

OB3

XxxNI n. From this eIN2 quation the value of gy is obtained. To find the altitude g M (fig. 55.) of the meta- Fig. 55center above the centre of gravity of the immersed part of the bottom, let the arc NS be described from the INXNS centre I with the radius IN; then NIn= Now since the two straight lines y M, gM are perpendicular to an and AN respectively, the angles M and NIn are therefore equal: and the infinitely little portion gy, which is perpendicular to g M, may be considered as an arch described from the centre M. Hence the two sec

2

tors NIS, g My are similar; and therefore g M: gy::
IN: NS.
INXY; and consequently
g M

Hence NS=

NI n=
former equation, and reduced, we have V Xgys
OB3× × ̧
But since g M and gy are the
& M
be under consideration, the
same, whatever section may
equation may therefore be expressed thus, V Xgr=
s, OB¦3×x. Hence g M=† 3, OB3×*. Let

INXg. Now this being substituted in the
2g M

3gy.

M:

M=

Xx

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To determine the value of gy, the momentum of
a Eb with respect to EO must be taken for the same
& M
reason as before, and put equal to the momentums of
the two parts AO a, AE b; and we shall then have y=OB, and the equation becomes g Ms, y
a Ebxgy, or AEBxgy=AEBxIL+AO axOh. Whence to have the altitude of the metacenter above
But since g is the common centre of gravity of the two
the centre of gravity of the immersed part of the bot-
spaces AE b, BO b, we shall have AE bxIL-BO b
tom, the length of the section at the water-line must be
XOk=0, or AEbxIL BObx0k. Hence AEB
divided by lines perpendicular to the middle line of this
xgy=B0 bx0 k+AO a ×0 h≈2BO b× O k; be-
section into a great number of equal parts, so that the
cause the two triangles AO a, BO b are equal, and that portion of the curve contained between any two adja-
the distances Ok, Ö h, are also evidently equal.
cent perpendiculars may be considered as a straight line.
Then the sum of the cubes of the half perpendiculars or
ordinates is to be multiplied by the distance between
the perpendiculars, and two-thirds of the product is to
be divided by the volume of the immersed part of the
bottom of the ship.

Let be the thickness of the section represented by ABC. Then the momentum of this section will be 2 BO b × x × О k, which equation will also serve for each particular section.

Now let s represent the sum of the momentums of all the sections. Hence s, AEB×a×gy=s, 2 Bob × × ×0 k. Now the first member being the sum of the momentums of each section, in proportion to a plane passing through the keel, ought therefore to be equal to the sum of all the sections, or to the volume of the immersed part of the bottom multiplied by the distance gy. Hence V representing the volume, we shall have VXgy=s, 2 BоbxxxОk.

In order to determine the value of the second member of this equation, it may be remarked, that when the ship is inclined, the original plane of floatation CBPQ VOL. XIX. Part I.

It is hence evident, that while the sector at the wa-
ter line is the same, and the volume of the immersed part
of the bottom remains also the same, the altitude of the
metacenter will remain the same, whatever may be the
figure of the bottom.

CHAP. IV. Of the Centre of Gravity of the immersed
Part of the Bottom of a Ship.

THE centre of gravity* of a ship, supposed homo- * See Mc-
geneous, and in an upright position in the water, is in a chonies.
PP
vertical

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